WebLet B and C be two events such that P(B) = 0.10 and P(C) = 0.31. A. Determine P(B \cup C) , give that B and C are independent. B. Determine P(B \cup C) , give that B and C are … WebIf A and B are independent events with P (A) = 0.2 and P (B) = 0.6, then P (A ∪ B) = 0.68 If A and B are independent events with P (A) = 0.05 and P (B) = 0.65, then P (A B) = 0.05 …
If P(B)=0.45, P(A B)=0.80, P(B
WebClick here👆to get an answer to your question ️ If P(A) = 0.25, P(B) = 0.50, P(A∩ B) = 0.14 , then P (neither A nor B) = Solve Study Textbooks Guides. Join / Login >> Class 12 >> … WebIf P(A) = 0.60, P(B) = 0.50, P(A and B) = 0.21, then P(A and not B) = (a) 0.39 (b) 0.11 (c) 0.29 (d) 0.50 (e) 0.21 Given that P(A) = 0.7, P(B) = 0.6, and P(A and B) = 0.35, calculate P(A' and B). Given that P(A) = 0.7, P(B) = 0.6, and P(A and B) = 0.35, calculate P(A' or B'). tow truck american truck simulator
if p( A intersection B) =0.60and p( A unionB) =0.70 for two events …
WebP (B) = 0.6. As A and B are independent events. P (A ∩ B) = P (A) × P (B) Substituting the values. P (A ∩ B) = 0.2 × 0.6. P (A ∩ B) = 0.12. We know that. P (A ∪ B) = P (A) + P (B) … Web11 jul. 2024 · Yes because P(A B) = P(A). Yes because P(A ∩ B) = 0. No because P(A B) ≠ P(A). No because P(A ∩ B) ≠ 0. c. Are events A and B independent? Yes because P(A B) = P(A). Yes because P(A ∩ B) = 0. No because P(A B) ≠ P(A). No because P(A ∩ B) ≠ 0. 29) The one-year return (in %) for 24 mutual funds is as follows: –2.4. 6.5 ... Web24 jun. 2024 · If P(A) = 0.50, P(B) = 0.60, and P(A B) = 0.30, then events A and B are a. mutually exclusive events b. not independent events c. independent events d. not … tow truck and dump truck cartoons